Answer:
x = 600 Km
Explanation:
given,
speed of transverse wave = 4.05 Km/s
speed of longitudinal wave = 7.695 Km/s
difference of the time of arrival of wave = 69.9 s
now,
t₂ - t₁ = 69.9 s
let x be the distance
x = 597.645 Km
x = 600 Km
distance of recorder from the site is 600 Km approximately.
a) Let's call x the direction parallel to the river and y the direction perpendicular to the river.
Dave's velocity of 4.0 m/s corresponds to the velocity along y (across the river), while 6.0 m/s corresponds to the velocity of the boat along x. Therefore, the drection of Dave's boat is given by:
relative to the direction of the river.
b) The distance Dave has to travel it S=360 m, along the y direction. Since the velocity along y is constant (4.0 m/s), this is a uniform motion, so the time taken to cross the river is given by
c) The boat takes 90 s in total to cross the river. The displacement along the y-direction, during this time, is 360 m. The displacement along the x-direction is
so, Dave's landing point is 540 m downstream.
d) If there were no current, Dave would still take 90 seconds to cross the river, because its velocity on the y-axis (4.0 m/s) does not change, so the problem would be solved exactly as done at point b).
Answer:
0.541 nm
Explanation:
The condition for maxima is,
Here, m=0,1,2,.....
And d is the slit separation, m is the order of maxima, is the wavelength.
Given that, the 17.3 eV electron posses a wavelength of
And the order of maxima is .
And the angle at which first order maxima occur is, .
Put these values in maxima condition while solving for d.
Therefore, the slit separation is 0.541 nm.