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iren2701 [21]
3 years ago
10

Write a recursive definition for the sequence 8,6,4,2...

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

  1. a1 = 8; an= an-1 - 2
  2. an = -3 + 4(n-1)

Step-by-step explanation:

1. The first step in problem solving is to look at the given information. Here, you can see that each number in the sequence is <em>2 less than the one before it</em>.

In the expression ...

  an = an-1 - 2

the term an-1 means the previous term, the term just before term an. So, this equation means the term of the sequence is <em>2 less than the one before it</em>. Since this matches the description of the sequence, this recursive relation is part of the correct answer. (The other part is the definition of the first term of the sequence: a1 = 8.)

The recursive definition is ...

  a_1=8;\ a_n=a_{n-1}-2

__

2. The given sequence has first term a1 = -3, and common difference d = 4. That is, each term is 4 more than the previous one. The explicit formula for an arithmetic sequence is ...

  an = a1 +d(n -1)

Filling in the given values gives you the explicit formula ...

  a_n=-3+4(n-1)

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B28%7D%20%2B%20%5Cfrac%7B1%7D%7B70%7D%20%2B%20%5Cfrac%7B1%7D%7B130%7D%20%2B%20
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Considering the least common multiple of the denominators, it is found that the result of the expression is given by:

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<h3>How do we add fractions?</h3>

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In this problem, the denominators are as follows: 28, 70, 130, 208, 304. Using a calculator, their lcm is of 138,320.

Considering equivalent fractions(the numerators are the division of the lcm by the previous denominator), the expression is:

\frac{4940}{138320} + \frac{1976}{138320} + \frac{1064}{138320} + \frac{665}{138320} + \frac{455}{138320} = \frac{4940 + 1976 + 1064 + 665 + 455}{138320} = \frac{9100}{138320}

More can be learned about the addition of fractions at brainly.com/question/78672

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