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Leni [432]
2 years ago
5

Find the slope of the line:

Mathematics
1 answer:
dlinn [17]2 years ago
6 0

Answer:

-1

Step-by-step explanation:

the line is written in slope intercept form making it easy to find that the slope is -1

slope intercept form is y= mx+b

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"Eighty and fifteen hundredths" in numbers<br>(decimals)
Black_prince [1.1K]

Answer:

80.15

Step-by-step explanation:

Eighty and fifteen hundredths = 80.15

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pentagon [3]

Answer:

cant see picture but it is an easy question based on equilateral that has 3 identical angles and is congruent. A Scalene has odd sides and is not congruent and an isosceles has two sides identical. You can also get two type of right angled triangle only 45 45 plus 90 for right angle would be be congruent

Step-by-step explanation:

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3 years ago
How do u get this?? I know the answer but then I don't know why they shuld divide by 2 I will mark the person who explains wit p
Greeley [361]

Answer:

10.89

Step-by-step explanation:

Circle:

C = TTD

C = TT(6.6)

C = 20.73451151

C = 20.73

Triangle:

A = bh/2

A = 6.6(3.3)/2        6.6/2=3.3

A = 21.78/2

A = 10.89

Shaded Region = 10.89

5 0
2 years ago
Is 3 a rational number or an irrational number
Sati [7]
It is a rational number
6 0
3 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
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