They’ve started out with 0yds of course so, -8yds on the first down. They’ve gained 20yds overall in both downs. You’re now trying to find “x”. -8+x=20. To find “x”, you do 20+8 because the 8 is negative and you would lose numbers in order to get 20, so “x” equals 28. Therefore, you’ve gained 28 yds in the second down and lost 8 yds in the first down.
I really, really hoped that helped. It took awhile to figure out, but I’m sure I’ve got it now.
Answer: There are 
ways of doing this
Hi!
To solve this problem we can think in term of binary numbers. Let's start with an example:
n=5, A = {1, 2 ,3}, B = {4,5}
We can think of A as 11100, number 1 meaning "this element is in A" and number 0 meaning "this element is not in A"
And we can think of B as 00011.
Thinking like this, the empty set is 00000, and [n] =11111 (this is the case A=empty set, B=[n])
This representation is a 5 digit binary number. There are 
of these numbers. Each one of this is a possible selection of A and B. But there are repetitions: 11100 is the same selection as 00011. So we have to divide by two. The total number of ways of selecting A and B is the 
.
This can be easily generalized to n bits.
Answer:
(x,y) ⇒ (x - 3) (y - 4)
C(5, -1)
Step-by-step explanation:
Answer:
46.3
Step-by-step explanation:
Find the number in the tenth place (2) and look one place to the right for the rounding digit (8) Round up if this number is greater than or equal to 5 and round down if it is less than 5
Thanks.
Answer is 37x=720-20+20-75-76+40=609
x=609/37= 16.459 Assuming all the numbers are the same as we can see it in the equation.
