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Nimfa-mama [501]
2 years ago
8

3.

Physics
1 answer:
mafiozo [28]2 years ago
3 0

Answer:

a) a = 1 [m/s²]

b) a = 0.25 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

a)

Between 0 and 2 seconds

 

where:

Vf = final velocity = 2 [m/s]

Vo = initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

Note: the positive sign of acceleration in the previous equation allows us to appreciate that the velocity is increasing

2 = 0 + a*2

a = 2/2

a = 1 [m/s²]

b)

Between 2 and 4 seconds

 

where:

Vf = final velocity = 2.5 [m/s]

Vo = initial velocity = 2

a = acceleration [m/s²]

t = time = (4 - 2) = 2 [s]

2.5 = 2 + a*2

2.5 - 2 = 2*a

0.5 = 2*a

a = 0.25 [m/s²]

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The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

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The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

<h3>Fₙ = 65 N to the left </h3>

Therefore, the net force acting on the car is 65 N to the left

Learn more on net force: brainly.com/question/19549734

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Which principle states that the net electrical force on a specific charge is equal to the sum of the vector components of the ch
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Answer:

Volume = 6248.48 m^{3}

Explanation:

Given:

The area of the house A = 2050\ ft^{2}

The height of the house h=10\ ft

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Solution:

We find the volume of the house by multiplying the area of the house and height of the house.

Volume = Area\times height

Volume = A\times h

Area and height of the house are known, so we substitute these value in above equation.

Volume = 2050\times 10

Volume = 20500\ ft^{3}

Now we convert the unit from feet to meter.

Divide the volume by 3.2808 for m^{3}

Volume = \frac{20500}{3.2808}

Volume = 6248.48\ m^{3}

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our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure
Dafna1 [17]

Answer:

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

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Mass m = 59 Kg

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Where \mu _{s} = coefficient of static friction, g = 9.8 \frac{m}{s^{2} }

Put the above values and find the coefficient of static friction.

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Therefore, the coefficient of static friction between your partner and the floor is 0.55

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