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Nimfa-mama [501]
2 years ago
8

3.

Physics
1 answer:
mafiozo [28]2 years ago
3 0

Answer:

a) a = 1 [m/s²]

b) a = 0.25 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

a)

Between 0 and 2 seconds

 

where:

Vf = final velocity = 2 [m/s]

Vo = initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

Note: the positive sign of acceleration in the previous equation allows us to appreciate that the velocity is increasing

2 = 0 + a*2

a = 2/2

a = 1 [m/s²]

b)

Between 2 and 4 seconds

 

where:

Vf = final velocity = 2.5 [m/s]

Vo = initial velocity = 2

a = acceleration [m/s²]

t = time = (4 - 2) = 2 [s]

2.5 = 2 + a*2

2.5 - 2 = 2*a

0.5 = 2*a

a = 0.25 [m/s²]

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Complete question:

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The magnitude of this field is 826 N/C

Explanation:

Given;

The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m

PEsinθ = T

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First, we determine the magnitude dipole moment;

Magnitude of dipole moment = q*r

P = 4.1 x 10⁻⁹ x 3.6 x 10⁻³ = 1.476 x 10⁻¹¹ C.m

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E = \frac{T}{P*sin(\theta)}=  \frac{7.3 X 10^{-9}}{1.476X10^{-11}*sin(36.8)}\\\\E = 825.6 N/C

E = 826 N/C (in three significant figures)

Therefore, the magnitude of this field is 826 N/C

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Answer:

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Explanation:

Given;

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The angular speed of the object is calculated as;

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