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yanalaym [24]
4 years ago
9

During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi

eld or steering wheel. According to safety standards, the bags produce a maximum acceleration of 60 g, but lasting for only 36 ms (or less).
How far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g?
Physics
1 answer:
vladimir2022 [97]4 years ago
7 0

Answer:

At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop

Explanation:

The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s

To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g

we write out the equation of motion thus.

S = ut + 0.5at²

wgere

S = distance to come to complete stop

u = final velocoty = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

as can be seen, the above equation calls up the given variable as a function of the required variable thus

S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m

At 60g, a person will travel a distance of 0.38 m before coing to a complete stop

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Answer:

a. The Earth orbits the sun

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Anchorage is the largest city in the United state of Alaska.

The major reason why we have seasons anywhere on the earth is the orbiting of the sun around the earth. Since the orbit of the earth is elliptical around the sun so it sometimes comes near the sun and sometimes far away from the sun due to which the average temperature of the earth keep varying during the entire year in phases of the distance from the sun.

When the earth is closer to the sun then the average temperature of the earth is relatively warmer than the average temperature when the earth is farther from the sun.

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D.

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The displacement z of a particle of rest mass m0, resulting from a constant force m0g along the z-axis is including relativistic
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Hi, your question was incomplete, hence I am writing down the complete question below.

Q)The displacement x of a particle of rest mass m0, resulting from a constant force m0g along the  x-axis, is

x= c2/g{[1+(gt/c)2]power0.5-1}

including relativistic effects. Find the displacement x as a power series in time t. Compare with  the classical result.

Answer:

<h3>Please refer to the attachment below.</h3>

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<h3>Please refer to the attachment below for explanation.</h3>

3 0
3 years ago
The International Space Station (ISS) orbits Earth in a nearly circular orbit that is 345 km above Earth's surface.
Tems11 [23]

Answer:

1) v = 7.70 10³ m/s , 2) F = 115 N and 3)    (F/W)% = 90.2%

Explanation:

1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal

    F = ma.

    F = G m M / r²

    a = v² / r

    G m M / r² = m v² / r

    G M / r = v²

Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth

    r = Re + 345 103

    r = 6.37 10⁶ + 3.45 10⁵

    r = 6.715 10⁶ m

Let's calculate the speed

   v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)

   v = 7.70 10³ m/s

The speed module is constant, so we can use the uniform motion relationships

   v = d / t

The distance is the length of the circle

   d = 2π r

   d = 2π 6.715 106

   d = 42.2 10⁶ m

Let's calculate the time

   t = d / v

   t = 42.2 10⁶ / 7.70 10³

   t = 5.48 10³ s

2) Let's use the universal gravitation equation

   F = G m M / r²

   F = 6.67 10⁻¹¹ 13.0  5.98 10²⁴ /(6.715 10⁶)²

   F = 11.5 10¹ N

   F = 115 N

3) in this for we are asked the relationship is out with the weight of the body on earth

   F / W = F / mg

   F / W = 115 / (13.0  9.8)

   F / W = 0.902

  F / W% = 90.2%

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