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KatRina [158]
3 years ago
10

A car mass 600kg starts from rest moving uniform acceleration 0.2 m/s^2 after 60 seconds collides with stationary pick up van of

mass 400kg gets locked with it and moves together with velocity 7.2 m/s
a) DOES THE PHENOMENON OF THE STEM SUPPORT THE PRINCIPLE OF CONSERVATION OF MOMENTUM? GIVE YOUR OPINION BY MATHEMATICAL ANALYSIS.​
Physics
1 answer:
galben [10]3 years ago
5 0

Answer:

the phenomenon of the system supports the principle of conservation of momentum.

Explanation:

The law of conservation of momentum says that:

Initial Momentum = Final Momentum

So, first we calculate initial momentum of the system:

Initial Momentum  = m₁u₁ + m₂u₂

where,

m₁ = mass of car = 600 kg

m₂ = mass of van = 400 kg

u₁ = Initial Speed of Car

For initial speed of car, we use:

Vf = Vi + at

Vf = 0 m/s + (0.2 m/s²)(60 s)

Vf = u₁ = 12 m/s

u₂ = Initial Speed of Van = 0 m/s

Therefore,

Initial Momentum  = (600 kg)(12 m/s) + (400 kg)(0 m/s)

Initial Momentum  = 7200 Ns   --------------- equation (1)

Now, for the final momentum:

Final Momentum  = m₁v₁ + m₂v₂

where,

v₁ = v₂ = Final Speed of Car and van (both are locked) = 7.2 m/s

Therefore,

Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)

Final Momentum = 7200 Ns   ------------- equation (2)

Comparing equation (1) and (2):

Initial momentum = Final Momentum

<u>Hence, the phenomenon of the system supports the principle of conservation of momentum.</u>

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Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to
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Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

<em>I will take two assumptions:</em>

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As we work with a linear charge density we work in one dimension, so the wire "has no radius"

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Answer:

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