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3 years ago

A boy weighs 40 kilograms. He runs at a velocity of 4 meters per second north. Which is his momentum?

1 answer:

4 0

The formula for momentum is mass times velocity. Simply, we just multiply the given values:
p = mv
p = 40 kg x 4 m/s
p = 160 kg m/s

Other units for momentum is N s.
p = 160 N s

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A certain car can accelerate from rest to 70km/h in 7 seconds.Find the cars average acceleration

Setler [38]

A= (70-0)/7
a=10 km/hr/sec

10 km/hr = 10 km*100 m/km/(1 hr*3=600 sec/hr)=25/9 m/sec
---------------------------------------------------------------------------------
a= 25/9 m/sec/sec

Hope this help, plz make brainly-est

4 0

3 years ago

Read 2 more answers

An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the

Igoryamba

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ( $a$ ), measured in meters per square second, is entirely centripetal and is expressed as:

$a = \frac{4\pi^{2}\cdot R}{T^{2}}$ (1)

Where:

$T$ - Period of rotation, measured in seconds.

$R$ - Radius of rotation, measured in meters.

If we know that $a = 26.36\,\frac{m}{s^{2}}$ and $R = 0.93\,m$ , then the time taken by the object to complete one revolution is:

$T^{2} = \frac{4\pi^{2}\cdot R}{a}$

$T = 2\pi\cdot \sqrt{\frac{R}{a} }$

$T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }$

$T \approx 1.180\,s$

The object takes approximately 1.180 seconds to complete one horizontal circle.

7 0

3 years ago

A stone dropped in a pond sends out a circular ripple whose radius increases at a constant rate of 4 ft/sec. After 12 seconds, h

Natali5045456 [20]

Answer:

After 12 seconds, the area enclosed by the ripple will be increasing rapidly at the rate of 1206.528 ft²/sec

Explanation:

Area of a circle = πr²

where;

r is the circle radius

Differentiate the area with respect to time.

$\frac{dA}{dt} = 2\pi r\frac{dr}{dt}$

dr/dt = 4 ft/sec

after 12 seconds, the radius becomes = $\frac{dr}{dt} X 12 = 4 \frac{ft}{sec} X 12 sec = 48 ft$

To obtain how rapidly is the area enclosed by the ripple increasing after 12 seconds, we calculate dA/dt

$\frac{dA}{dt} = 2\pi r\frac{dr}{dt}$

$\frac{dA}{dt} = 2\pi (48)(4)$

dA/dt = 1206.528 ft²/sec

Therefore, after 12 seconds, the area enclosed by the ripple will be increasing rapidly at the rate of 1206.528 ft²/sec

7 0

3 years ago

If a projectile fired beneath the water, straight up, breaks through the surface at a speed of 13m/s, to what height above the w

OlgaM077 [116]

Well if you had either the velocity or distance traveled i could tell you. But since you haven't all i can say for sure is that the water slowed the bullet down to 13m/s so lets say you knew the distance you would calculate how many meters it traveled and you would have your answer because in this situation, meters (height) =how many seconds spent going into the air.

3 0

3 years ago

A bird takes off from the tree and after 5 s is flying at a speed of 10 m/s. Calculate

Volgvan

Answer:

10miles/second

Explanation:

Change in velocity of the bird is expressed as the difference between the final velocity and initial velocity of the body.

Change in velocity = Final velocity - initial velocity

Since the bird takes off from the tree, the initial velocity of the bird = 0miles/sec

Final velocity = 10miles/secs

Change in velocity = 10-0

Change in velocity = 10miles/second

6 0

2 years ago