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3 years ago

11

PLEASE HELP WHAT IS THE GREATEST INTEGER THAT ALWAYS DIVIDES THE DIFFERENCE OF SQUARES OF ANY TWO POSITIVE ODD INTEGERS PLEASEEE

E

1 answer:

cestrela7 [59]3 years ago

4 0

I believe it’s 1 the answer

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45 + 60 = 15 x ___ + 15 x ___

tia_tia [17]

Answer:45+60=15x+15x

Step 1: Simplify both sides of the equation.

45+60=15x+15x

(45+60)=(15x+15x)(Combine Like Terms)

105=30x

105=30x

Step 2: Flip the equation.

30x=105

Step 3: Divide both sides by 30.

30x/30= 105/30

x= 7/2

Answer:

x= 7/2

may i have brainliest please

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3 years ago

Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?

Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: $y = 3 \cos(10 (x -\pi))$

We can assume the parent function to be:

$y = \cos (x)$

The new function can be represented as:

$y = A*\cos((\frac{2\pi}{B})(x-c))$

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

$y = A*\cos((\frac{2\pi}{B})(x-c))$ to $y = 3 \cos(10 (x -\pi))$

$A = 3$

$c = \pi$

$\frac{2\pi}{B} = 10$

Solve for B

$B = \frac{2\pi}{10}$

$B = \frac{\pi}{5}$

Using the calculated values of $A,\ B\ and\ c.$ This implies that, the following transformations occur on the parent function:

<em>Vertically stretched by </em> $3$ <em />
<em>Horizontally compressed by </em> $\frac{\pi}{5}$ <em />
<em>Right shifted by </em> $\pi$ <em />

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To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.

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Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle

worty [1.4K]

$5th \: row = 1 \: \: \: 5 \: \: \: 10 \: \: \: 10 \: \: \: 5 \: \: \: 1$

$(x - 4) {}^{5} = x {}^{5} + 5x {}^{4} ( - 4) {}^{1} + 10x {}^{3} ( - 4) {}^{2} + 10x {}^{2} ( - 4) {}^{3} + 5x( - 4) {}^{4} + ( - 4) {}^{5}$

$(x - 4) {}^{5} = x {}^{5} - 20x {}^{4} + 160x {}^{3} - 640x {}^{2} + 1280x - 1024$

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2 years ago