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Paraphin [41]
3 years ago
11

PLEASE HELP WHAT IS THE GREATEST INTEGER THAT ALWAYS DIVIDES THE DIFFERENCE OF SQUARES OF ANY TWO POSITIVE ODD INTEGERS PLEASEEE

E
Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0
I believe it’s 1 the answer
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45 + 60 = 15 x ___ + 15 x ___
tia_tia [17]

Answer:45+60=15x+15x

Step 1: Simplify both sides of the equation.

45+60=15x+15x

(45+60)=(15x+15x)(Combine Like Terms)

105=30x

105=30x

Step 2: Flip the equation.

30x=105

Step 3: Divide both sides by 30.

30x/30= 105/30

x= 7/2

Answer:

x= 7/2

may i have brainliest please

3 0
3 years ago
Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?
Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: y = 3 \cos(10 (x -\pi))

We can assume the parent function to be:

y = \cos (x)

The new function can be represented as:

y = A*\cos((\frac{2\pi}{B})(x-c))

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

y = A*\cos((\frac{2\pi}{B})(x-c)) to y = 3 \cos(10 (x -\pi))

A = 3

c = \pi

\frac{2\pi}{B} = 10

Solve for B

B = \frac{2\pi}{10}

B = \frac{\pi}{5}

Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

  • <em>Vertically stretched by </em>3<em />
  • <em>Horizontally compressed by </em>\frac{\pi}{5}<em />
  • <em>Right shifted by </em>\pi<em />
5 0
3 years ago
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How do you do 4x - 9 = 6x - 13? what do you subtract from both sides?
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To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.

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3. Solve the system of equations using linear combination. <br><br> a + c = 9<br> 8a + 4.5c = 58
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Hey I have posted a picture the method I use to solve simultaneous equations is change the sign and follow the new sign.
This involves changing the sign for the second equation and solving it

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Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle
worty [1.4K]

5th \: row = 1 \:  \: \:  5 \: \:   \: 10 \:  \:  \: 10 \:  \: \:  5 \: \:   \: 1

(x - 4) {}^{5}  = x {}^{5}  + 5x {}^{4} ( - 4) {}^{1}  + 10x {}^{3} ( - 4) {}^{2}  + 10x {}^{2} ( - 4) {}^{3}  + 5x( - 4) {}^{4}  + ( - 4) {}^{5}

(x - 4)  {}^{5}  = x {}^{5}  - 20x {}^{4}  + 160x {}^{3}  - 640x {}^{2}  + 1280x  - 1024

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