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Aleks [24]
4 years ago
15

What improper fraction equal to the mix number 4 7/9?

Mathematics
1 answer:
Marianna [84]4 years ago
3 0

Answer:

43/9

Step-by-step explanation:

Step 1

Multiply the denominator by the whole number

9 × 4 = 36

Step 2

Add the answer from Step 1 to the numerator

36 + 7 = 43

Step 3

Write answer from Step 2 over the denominator

43/9

=439

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Determine which of the following equations, when graphed, intersect at the point (4, 0).
kakasveta [241]

Answer:

Hence, the following equations, when graphed, intersect at the point (4, 0):

x - y = 4 (1)

x + y = 4 (4)

Step-by-step explanation:

<em>" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".</em>

1)

x-y=4

now when y=0 then x=4.

Hence, the graph intersect at the point (4,0).

2)

-x-y=4

When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.

3)

2x-y=7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

4)

x+y=4

When y=0 then x=4.

Hence the graph of the given function intersect at (4,0).

5)

2x + y = 7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

6)

2x + y = -7

When y=0 then x= -7/2.

Hence the graph of the function does not intersect at the point (4,0).


3 0
3 years ago
Evaluate the expression 7^2/x^2-2 for x =3
Elan Coil [88]

Answer:

7^2/x^2-2 for x =3

49/9-2

49/7

7

answer is 7

Step-by-step explanation:

8 0
3 years ago
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

8 0
4 years ago
What is the surface area of a sphere with a diameter of 2.7 inches?
olga nikolaevna [1]

Answer:

22.9

Step-by-step explanation:

7 0
4 years ago
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The supplement of angle t is 4 times the measure of angle t
Dimas [21]
The answer is 45 because supplement means the sum of 180 so 180 divided by 4 is 45 and t=45
3 0
3 years ago
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