Ask question

Ask question

All categories

2 years ago

10

Ben writes the number 74,443. The value of the digit 4 in the hundreds place is 10 times the value of the digit 4 in what place

value ?

2 answers:

slega [8]2 years ago

4 0

In the "tens place". One hundred is ten times ten, so four hundred is ten times forty.

natta225 [31]2 years ago

3 0

It's ten times the value of the digit 4 in the tens place

You might be interested in

You are going to decorate one wall of your bedroom by putting a border along the top. The wall is a square wall with an area of

e-lub [12.9K]

Answer:

16 ft

Step-by-step explanation:

Each edge of wall = √256 ft = 16 ft

5 0

2 years ago

What is the y intercept of this graph of this graph

kompoz [17]

Answer:

i cant entirely see the image well, but the<u> y intercept</u> should be the line that passes through the line on the graph that goes <u>up and down</u>

<u>Step-by-step explanation:</u>

i hope this helps :))

8 0

2 years ago

Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)

Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: $L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

point C can be info set 1: (10, -1) x₁ = 10 y₁ = -1

point D can be info set 2: (-6, 3) x₂ = -6 y₂ = 3

Substitute the information into the formula

$L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

$CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }$ Simplify inside each bracket

$CD = \sqrt{(-16)^{2}+(4)^{2} }$ Square the numbers

$CD = \sqrt{256+16 }$ Add inside the root

$CD = \sqrt{272}$ Enter into calculator

$CD = 16.5$ Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0

3 years ago

4x^2-12x-1=0 in quadratic form

Tom [10]

Answer:

Step-by-step explanation:

8 0

2 years ago

Y=-2x²-8x-5 domain and range

Jobisdone [24]

Answer:

Domain: All real numbers

Range: y≤3

Step-by-step explanation:

The given function is

$y = - 2 {x}^{2} - 8x - 5$

This is a polynomial function.

The domain is set of all values of x, that makes this function defined.

Since polynomial functions are defined everywhere, the domain is all real numbers.

To find the range we put the function in vertex form:

$y = - 2( {x}^{2} + 4x) - 5$

$y = - 2( {x}^{2} + 4x + 4) - 5 + - 4 \times - 2$

$y = - 2( {x} + 2)^{2} - 5 + 8$

$y = - 2( {x} + 2)^{2} + 3$

The maximum value is 3

The function turns downward, hence the range is:

$y \leqslant 3$

6 0

2 years ago