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Kruka [31]
3 years ago
12

............................................... .

Chemistry
1 answer:
Sergio [31]3 years ago
5 0

Answer:

yuh

Explanation:

You might be interested in
An atom of Silver loses three electrons, what is its charge?
Dovator [93]

Answer:

+3

Explanation:

If an atom loses electrons, it becomes positive. Because silver loses 3 electrons, the charge becomes positive 3.

3 0
3 years ago
How many grams of nitroglycerin are needed to produce 25.0 grams of CO2
LekaFEV [45]
N<em>itroglycerin  decomposes    according  to   the   following  equation

4 C3H5N309  --->  12 CO2 +  10 H20  +  6 N2 +O2
The  moles  of  CO2 =  25 /44(molar  mass  of  CO2)=  0.568  moles

the  mole  ratio  of  C3H5N3O9  to  CO2  IS  4:12   from  equation  above
therefore  the  moles  of  C3H5N3O9=( 0.568 x 4)/12= 0.189  moles
mass  of C3H5N3O9=moles  x  molar  mass  of  C3N5N3O9

That  is    0.189 mol x  227  g/mol=  42.903  grams</em>
8 0
4 years ago
Explain how you can convert from the number of representative particles of a substance to moles of that substance.
Scrat [10]

Answer:

  • the number of representative contain in 1 mol of a substance equals to 6.o2x10^23 particles.
8 0
3 years ago
Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the
NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' =  Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0
3 years ago
How many grams of coffee must evaporate from 350 g of coffee in a 100-g glass cup to cool the coffee and the cup from 95.0°C to
Natali5045456 [20]

Answer:

31.3 g

The answer is higher than the true answer.

Explanation:

By neglecting the heat lost by other processes, the energy conservation states that:

Qcooling + Qevaporate = 0

The cooling process happens without phase change, so the heat can be calculated by:

Qcooling = m*c*ΔT

Where m is the mass, c is the heat capacity (cwater = 4184 J/kg.K), and ΔT is the temperature variation (final - initial).

The evaporate process happen without changing of temperature (pure substance), and the heat can be calculated by:

Qevaporate = m*L

Where m is the mass evaporated and L is the heat of evaporation (2340000 J/kg).

0.350*4184*(45 - 95) + m*2340000 = 0

2340000m = 73220

m = 0.0313 kg

m = 31.3 g

Because of the assumptions made, the real mass is not that was calculated. There'll be changing mass when the coffee is cooling, and there'll be heat loses by other processes because the system is not isolated. Also, the substance is not pure. So, there'll be more factors at the energy equation, thus, the answer is higher than the true answer.

6 0
4 years ago
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