Even though Hydrogen is originally in group 1, based on this property, we can say it is in group 6.
Because:
Group 6 would mean that it only needs 2 more valence electrons till the octet (8 valence electrons). This would make it reactive, yet, in normal conditions, unlike group 7.
Answer:
V CH4(g) = 190.6 L
Explanation:
assuming ideal gas:
∴ STP: T =298 K and P = 1 atm
∴ R = 0.082 atm.L/K.mol
∴ moles (n) = 7.80 mol CH4(g)
∴ Volume CH4(g) = ?
⇒ V = RTn/P
⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)
⇒ V CH4(g) = 190.6 L
Answer:
NO2 is the molecular formula of nitrogen Oxide
Explanation:
Correct question
An oxide of nitrogen contain its own volume of nitrogen
its vapour dentity is 23. Find the molecular formula
Of nitrogen Oxide
Solution
As we know
Molecular Weight is equal to two times the vapour density
Hence, the molecular weight of Oxide of nitrogen is 2 * 22 = 44
Molecular weight of Oxide of nitrogen is the sum of atomic weight of nitrogen and oxygen
Molecular weight of Oxide of nitrogen = 14 + 16 *Y
14 + 16 *Y = 46
Y = 2
Hence, the formula is NO2
Answer:- 537 kJ of heat is released.
Solution:- For the given equation, 
is -657 kJ and the coefficient of 
in the balanced equation is 2. It means 657 kJ of heat is released when 2 moles of chlorine are used. We need to calculate the heat released when 116 g of are used.
Grams of chlorine are converted to moles and then multiplied by the value and divided by the coefficient of chlorine and the set could be shown using dimensional analysis as:
= 537.46 kJ
If we use the correct sig figs then it needs to be round off to three sig figs as the given grams of chlorine has only three sig figs. So, 537 kJ of heat is released.
