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ziro4ka [17]
3 years ago
14

For the reaction of reducing benzil (MW 210.23 g/mol) with sodium borohydride (MW 37.83 g/mol), if 2.56 g of benzil and 0.38 g o

f sodium borohydride were used to make hydrobenzoin (MW 214.26 g/mol), and 2.22 g of hydrobenzoin was obtained, which chemical is limiting reagent
Chemistry
1 answer:
disa [49]3 years ago
7 0

Answer:

NaBH₄

Explanation:

First, we need to write the chemical formula of all the compounds:

Benzil: C₁₄H₁₀O₂

Sodium Borhydride: C₁₄H₁₀O₂

Hydrobenzoin: C₁₄H₁₄O₂

Now, let's write the reaction that is taking place and write all the products:

C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH

We can see that the reaction is already balanced, so we don't need to do anything else.

The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)

According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:

moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles

moles NaBH₄ = 0.38 / 37.83 = 0.01 moles

moles  C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles

We have the moles of every species, now, let's see the mole ratio

If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄

Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄

Solving for X:

X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.

However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄

Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.

<h2>So, in conclusion, Limiting reagent NaBH₄</h2>

Hope this helps

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Use the periodic table to classify each of the elements below.
Alika [10]

Answer:

Explanation:

Cadmium:(Cd)

Cadmium is transition metal present in group twelve. It is soft metal and properties are similar to the other group members like zinc and mercury. Its atomic number is forty eight and have two valance electrons.

Electronic configuration:

Cd₄₈ = [Kr] 4d¹⁰ 5s²

Vanadium: (V)

It is present in group five. It is malleable and ductile transition metal. Its atomic number is twenty three. Vanadium have five valance electrons.

Electronic configuration:

V₂₃ =[Ar] 3d³ 4s²

Xenon: Xe

Xenon is present in group eighteen. It is noble gas. Its outer most valance shell is complete that's why it is inert. its atomic number is fifty four. Xenon have eight valance electrons.

Electronic configuration:

Xe₅₄ = [Kr] 4d¹⁰ 5s² 5p⁶

Iodine: (I)

Iodine is present in group seventeen. Its outer most valance shell have seven electrons. Iodine is the member of halogen family. It gain one electron to complete the octet. its atomic number is fifty three.

Electronic configuration:

I₅₃ = [Kr] 4d¹⁰ 5s² 5p⁵

Potassium: (K)

Potassium is present in group one. it is alkali metal. Its atomic number is nineteen. Its valance shell has one electron. Potassium loses its one valance electron and gets stable electronic configuration.

Electronic configuration:

K₁₉ = [Ar] 4s¹

Strontium: Sr

Strontium is present in group two. it is alkaline earth metal. its atomic number is thirty eight and have two valance electrons.

Electronic configuration:

Sr₃₈ = [Kr] 5s²

5 0
3 years ago
Read 2 more answers
Which statement describes a scientific law?
Sholpan [36]

Answer:

A law is a proven fact that can not be changed.

Explanation:

Scienctists are most inquisitive in their research and as such they developed what is called scientific method which they use to create and learn new things. The scientific method includes:

1. Observation.

2. Hypothesis.

3. Experiment

4. Conclusion.

5. Law.

Among this scientific method, the law is the last in the pattern. A law is only given after the experiment has been tested over and over again and found to be true.

4 0
3 years ago
20 L of nitrogen gas are collected at a temperature of 50°C and 2 atm. How many grams of nitrogen gas were collected?
Andreas93 [3]

Answer:

0.1077 grams

Explanation:

First we will employ the ideal gas law to determine the number of moles of nitrogen gas.

PV=nRT

P=2 atm

V=20L

R=0.08206*L*atm*mol^-1*K^-1

T=323.15 K

Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K

K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles

Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.

1.5/14=0.1077 grams

8 0
2 years ago
Can you unhelpful people answer this question already i'll mark you the brainlest. I'll mark you the brainlest if you answer the
Genrish500 [490]
A. only volume (cm^3)

Explanation:
The independent variable is typically represented as x. It is the variable that you change during the experiment. In this graph, as volume increases, it increases the mass too. Hope this helps!
5 0
2 years ago
What is the mass of 8.12×10 to the 23rd power molecules of CO2 gas
Maksim231197 [3]

Answer:

38.7 g is the answer to your question. Your welcome:)

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