Answer:
The load distance is 4.9 cm
Explanation:
Given;
Effort applied to the lever, E = 120 N
Load overcame by the effort, L = 50 kg = 50 x 9.8 = 490 N
distance of the effort from the fulcrum, e = 20 cm
let the distance of the load from the fulcrum = d
The following simple set-up is used to illustrate this lever;
-----------------------------Δ-------------------------------
↓ 20cm d ↓
120 N 490 N
Lever operates on the principle of moment, so take moment about the pivot (fulcrum);
490(d) = 120(20)
d = (120 x 20) / (490)
d = 4.9 cm
Therefore, the load distance is 4.9 cm
