I’ll say D , hope this helps u
Step-by-step explanation:
What exactly are you asking for help w?
Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
We need the diagram pic, otherwise we cant solve your problem.
Answer is choice C) cosine is even; sine is odd
The properties that come with even and odd functions are...
f(-x) = f(x) indicates we have an even function. So cos(-x) = cos(x)
f(-x) = -f(x) indicates we have an odd function. So sin(-x) = -sin(x)
note: the end result of the proof will lead to cos(A)cos(B)+sin(A)sin(B)
