Pythagorean theorem HELP PLZ i am doing other ones can you plz do this one

Mathematics

2 answers:

aivan3 [116]3 years ago

5 0

Answer:

it is the 1st one.

Step-by-step explanation:

The pythagorean theorem is $a^{2} + b^{2} = c^{2}$ , a and b standing for the two legs and c stands for the hypotenuse (slanted line connecting the two). Since $2^{2} = 4$ and $3^{2} = 9$ , we add 4 and 9 to get 13. Since 3 is already squared, we can look at it like $\sqrt{13}$ . Therefore, the first answer, "2,3, $\sqrt{13}$ ", is correct. Hope this helped!! :]

xenn [34]3 years ago

3 0

Answer:

it is the first answer

Step-by-step explanation:

have a good day :)

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Answer:

3x^2 + 7x - 18

Step-by-step explanation:

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3 years ago

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The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

5 0

3 years ago

5p-3r=1

Brilliant_brown [7]

If you would like to solve the system of equations, you can do this using the following steps:

5p - 3r = 1 /*2
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10p - 6r = 2
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5p - 3r = 1
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5/3 - 3r = 1
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(p, r) = (1/3, 2/9)

The correct result would be (1/3, 2/9).

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