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AleksandrR [38]
3 years ago
13

Todd plans to swim 18 laps in a pool. Each lap 50 yards.so far Todd has swam 738 yards what percentage of the total has Todd com

pleted
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

He is 82 percent done

Step-by-step explanation:

by multiplying 18 laps by 50 yards we have to total distance of 900 yards

so using the equation (738/900) * 100 we get 82

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Ozzie has a coupon for 5% off any purchase in his favorite bakery. When Ozzie stops to buy some cookies, he discovers that all c
maria [59]

Answer:

D

Step-by-step explanation:

you need to first do 5.89- [(5.89 * 15)/100]=5.89-0.8835=5.0065

then 5.0065 * 2 = 10.013 because it is 15% each dozen then

[(10.013 * 5)/100] =0.50065 then 10.013 - 0.50065 = 9.51235

and lastly (9.51235 * 7)/100 = 0.6658645

finally 9.51235 + 0.6658645= 10.1782145

and then you just need to round it to the nearest hundredths and you will get 10.18

4 0
2 years ago
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Two thirds of a number reduced by 11 is equal to 4 more than the number. Find the number. n= Answer
Ira Lisetskai [31]

Answer:

-45

Step-by-step explanation:

2/3x - 11 = x + 4

  • I created an inequality representing the above statement first. This makes things look less complicated than what the question is asking.

2/3x = x + 15

  • solve for x. I started by adding 11 to both sides.

-1/3x = 15

  • multiply both sides by -3

x = -45

8 0
2 years ago
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42+58=n+60 the answer for this problem
seraphim [82]
The answer is n= 40.

5 0
3 years ago
Evaluate f(6) = 9 - 2x.<br><br> a<br> - 42<br> b<br> 21<br> c<br> - 3<br> d<br> 1
Ivenika [448]

Answer:

f(6) = -3

Step-by-step explanation:

9-2(6)

9-12

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3 0
3 years ago
Rewrite the expression in the form y^ny n y, start superscript, n, end superscript. \dfrac{1}{y^{^{\scriptsize\dfrac54}}}= y 4 5
just olya [345]

Answer:

The expression can be rewritten in y^n form as following:

⇒  y^{-\frac{5}{4}}

where n=-\frac{5}{4}

Step-by-step explanation:

Given expression:

\dfrac{1}{y^{^{\scriptsize\dfrac54}}}

To rewrite the expression in the form of y^n.

Solution:

By property of exponents :

\frac{1}{x^a}=x^{-a}

<em>So, we can apply this property to the given expression.</em>

We have:

\dfrac{1}{y^{^{\scriptsize\dfrac54}}}

⇒  y^{-\frac{5}{4}}

The above expression is in the form of y^n where n=-\frac{5}{4}

8 0
3 years ago
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