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3 years ago

9

Anyone got the answer?(^•^)

2 answers:

Vladimir79 [104]3 years ago

6 0

Answer:

8

Step-by-step explanation:

Step-by-step on how to solve it is in the image below.

Happy to help! :)

malfutka [58]3 years ago

3 0

Answer:

It's 8

Step-by-step explanation:

$16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8$

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96.3 cm measured to the nearest tenth of a cm

rjkz [21]

Answer:

96.3 cm measured to the nearest tenth of a cm is 100 cm

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2 years ago

I WILL GIVE BRAINLIEST!!!

zimovet [89]

Not equivalent to any of the given expressions.

Step-by-step explanation:

${7}^{2m} . {6}^{2m} \\ \\ = (7.6) ^{2m} \\ \\ = {42}^{2m}$

Hence, ${42}^{2m}$ is not equivalent to any of the given expressions.

6 0

3 years ago

Read 2 more answers

Solve this inequality: 3b – 7 < 32

butalik [34]

It's a lot like solving equations.

3b-7 < 32
Add 7 to each side.
3b < 39
Divide by 3 on each side.
b < 13

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

<u>Given:</u>

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

<u>Solve for </u> $x$ <u> in the 1st equation:</u>

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

<u>Substitute the value of </u> $x$ <u> into the 2nd equation and solve for </u> $z$ <u>:</u>

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

<u>Substitute the value of </u> $z$ <u> into the 3rd equation and solve for </u> $y$ <u>:</u>

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

<u>Plug </u> $y=3$ <u> into the solved expression for </u> $z$ <u> and evaluate to solve for </u> $z$ <u>:</u>

$z=16-7(3)$

$z=16-21$

$z=-5$

<u>Plug </u> $z=-5$ <u> into the solved expression for </u> $x$ <u> and evaluate to solve for </u> $x$ <u>:</u>

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

6 0

3 years ago

if trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A’lie

maria [59]

Answer:

<em>Answer: (second option) (-4,1)</em>

Step-by-step explanation:

<u>Transformations of Points and Shapes</u>

The image shows a trapezoid ABCD where point A has coordinates (-4,1).

The following transformations are performed:

Reflection over the y-axis: If a point (x,y) is reflected over the y-axis, it becomes (-x,y). Thus point A becomes A'=(4,1)

Reflection over the x-axis: If a point (x,y) is reflected over the x-axis, it becomes (x,-y). Thus point A' becomes A''=(4,-1)

Rotation 180°: If a point (x,y) is rotated 180°, it becomes (-x,-y). Thus point A'' becomes A'''=(-4,1)

Answer: (second option) (-4,1)

5 0

3 years ago