All categories

2 years ago

Solve the system: x - y = 5 4x – 5 y =17

Mathematics

1 answer:

diamong [38]2 years ago

8 0

Answer:

8,3

Step-by-step explanation:

You might be interested in

Fill in the blank to complete the equation. Then find quotion 5÷1/2

hichkok12 [17]

I'm not sure about the equation, but the quotient to 5 ÷ $\frac{1}{2}$ = 10.

"KEEP IT, CHANGE IT, FLIP IT." This is applied to find the quotient, and once done, the answer is found to be 10.

5 0

3 years ago

11.25 for 2/3 pound how much per pound?

Artist 52 [7]

Divide 11.25 by (2/3). The answer is 16.875

6 0

3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Calculate 6.75 tax on 23.05

Ksenya-84 [330]

The answer is 12dollas

3 0

2 years ago

PLEASE HELP ILL GIVE BRAINLIEST

DanielleElmas [232]

Option A:

$(x-5)^{2}+(y-3)^{2}=16$

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

$(x-5)^{2}+(y-3)^{2}=4^{2}$

$(x-5)^{2}+(y-3)^{2}=16$

The equation of the given circle is $(x-5)^{2}+(y-3)^{2}=16$ .

Hence Option A is the correct answer.

5 0

2 years ago