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lisov135 [29]
4 years ago
9

A 1.0-c point charge is 15 m from a second point charge, and the electric force on one of them due to the other is 1.0 n. what i

s the magnitude of the second charge?
Physics
1 answer:
Fofino [41]4 years ago
4 0
The answer is 25nC !!! 

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A satellite travels with a constant speed |v| as it moves around a circle centered on the earth. How much work is done by the gr
7nadin3 [17]

Answer:

W = 0

Explanation:

As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by

      W = F. r = f r cos θ

Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.

W = 0

3 0
3 years ago
Complete the electron-pushing mechanism for the e1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid.
Sav [38]
E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.

The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O. 
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.

The product is 2-methyl-2-butene.


6 0
4 years ago
Read 2 more answers
A high school physics student claims her muscle car can achieve a constant acceleration of 10 ft/s/s. Her friend develops an acc
Nikolay [14]

Answer: Ф = 17.2657 ≈ 17°

Explanation:

we simply apply ET =0 about the ending of the rod

so In.g.L/2sinФ - In.a.L/2cosФ = 0

g.sinФ - a.cosФ = 0

g.sinФ = a.cosФ

∴ tanФ = a/g

Ф =  tan⁻¹ a / g

Ф = tan⁻¹ ( 10 / 32.17405)

Ф = tan⁻¹ 0.31080948777

Ф = 17.2657 ≈ 17°

Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°

5 0
3 years ago
Number of atoms in a formula​
zimovet [89]
The formula must have at least 2 atoms
4 0
3 years ago
A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are​ added, the period becomes 33 sec. Assuming that
polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring    

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

T=2\pi \sqrt{\frac{m}{k}}, here m is mass and k is spring constant

From the relation we can see that

\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}

\frac{22}{33}=\sqrt{\frac{m}{m+22}}

Squaring both side

0.444={\frac{m}{m+22}}

0.444m+9.777=m

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0
3 years ago
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