All categories

3 years ago

We reduce friction in machines? why

Physics

2 answers:

Alexxandr [17]3 years ago

6 0

Answer:

Because it causes a lot of wear and tear in machine parts that move against each other. It erodes the surfaces and destroys their symmetries

Explanation:

kvv77 [185]3 years ago

5 0

Answer:

friction reduces the efficiency of machines, thus we must reduce the friction force that is acting upon it.

You might be interested in

Freee pointssss!!!! loveee y'allll

melamori03 [73]

Answer:

yay thank u have a great dayy!!

Explanation:

5 0

3 years ago

Read 2 more answers

2. A hydraulic lift is used to lift heavy machine pushing down on a 5 square meters piston with a force of 1000 N. What force ne

IRINA_888 [86]

Answer:

The force needs to be applied on the 1 square meter piston to lift the machine is 200 N.

Explanation:

Given that,

Force, $F_1=1000\ N$

Area, $A_1=5\ m^2$

We need to find the force needs to be applied on the 1 square meter piston to lift the machine. We know that the pressure at every point is same due to Pascal's law such that :

$P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\\dfrac{1000}{5}=\dfrac{F_2}{1}\\\\F_2=200\ N$

So, the force needs to be applied on the 1 square meter piston to lift the machine is 200 N. Hence, this is the required solution.

3 0

4 years ago

Read 2 more answers

2. The force between charges is 7 N. The distance between the charges is 4 x 10-6 m. If one of the charges is 2 x 10-8 C, what i

g100num [7]

Answer:

2) 6.22 × 10^-13

3) 4.56 × 10^-4

Explanation:

4 0

3 years ago

The electron dot diagram shows the arrangement of dots without identifying the element.

olasank [31]

Answer: tellurium (Te)

atomic number = 52 ,

Number of energy levels = 5;

First energy level = 2

Second energy level = 8

Third energy level = 18

Fourth energy level = 18

Fifth energy level = 6

In this electron configuration, 0uter most electrons are 6.

5 0

3 years ago

Read 2 more answers

The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.

dmitriy555 [2]

The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get,

d = [n*MW]/ Na*[a^3]
d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3]
d = 0.719 g/cm3

4 0

4 years ago

We reduce friction in machines? why​

We reduce friction in machines? why