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MArishka [77]
2 years ago
15

The triangle and the rectangle have the same area

Mathematics
1 answer:
Murljashka [212]2 years ago
5 0

Answer:

w =2.5

Step-by-step explanation:

the area of the triangle is 6*5 divided by half which is 15. this means that the area of the rectangle is also 15. so to find the value of the width we have to divide the area by the known value to get our answer. 15/6 is equal to 2.5 so that's what the value of w is.

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Please please please help me. I have no idea what to do
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We have a bunch of rectangles making up the lateral sides of this figure. They have side length 12 and height 13.

So the area of one rectangle is 12 x 13 = 156.
We have 6 of these rectangles, so our lateral area is 6(156) = 936.

The total surface area requires that we include the area of the base. To find the area of a regular polygon we take half of the product of the apothem and perimeter.

A = (1/2)*a*p

The apothem is given to be 10.39,
and the perimeter is fairly easy to calculate:
With the side length being 12, the perimeter is then 6(12) = 72.

So then the area of our base is (1/2)*10.39*72 = 374.04

So then the total surface area is the (base area) + (lateral area),
374.04 + 936 = 1310.04
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HELP MEEE!! What's the domain and range?
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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

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