Answer:
Dear Students and Families: It has come to our attention that families and students have been contacted regarding the replacement of chrome books being used by students. Please disregard these requests, as they are not affiliated with GEE Prep. If anyone reaches out to you, please contact us and we will look into it. Only GEE Prep staff will reach out regarding the replacement of any student chrome books. Thank you.
Step-by-step explanation:
Answer:
Option (1)
Step-by-step explanation:
System of equations is represented by two straight lines on a graph.
And solution of the system of equations is the point of intersection of these lines.
From the graph attached, two straight lines represent the system of equations.
And the point of intersection of these lines is the solution.
Therefore, solution of the system of equations will be (-6, -2).
Option (1) will be the correct option.
Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
__
Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
Answer:
10/1 +54/-6
Step-by-step explanation:
Is this the answer?
Answer:
<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>
Step-by-step explanation:
To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.
at x = 0;
f(0) = 16 + 2(0) − 0²
f(0) = 16
at the other end point i.e at x = 5;
f(5) = 16 + 2(5) − 5²
f(5) = 16 + 10-25
f(5)= 26-25
f(5) = 1
The absolute minimum value is 1 and occurs at x = 5
The absolute maximum value is 16 and occurs at x = 0
