Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%
The confidence interval is
(p - 1.96k, p + 1.96k)
where

Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)
Answer: The 95% confidence interval is (19.4%, 20.6%)
Answer:
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Step-by-step explanation:
<span>The first step you need to do is to rewrite
x+y=3
as y=3-x
</span><span>Now we can replace the y in the equation with our newfound value for y, which is
y=3-x.
So lets write it now like this
Q=x^2+2(3-y)^2
=x^2+18-12x+2x^2
=3x^2+18-12x
</span>Hope this helps
Answer:

Step-by-step explanation:
Considering the expression

Lets determine the expansion of the expression




Expanding summation








as





so equation becomes


Therefore,