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Serggg [28]
3 years ago
15

Suppose that a red die and a green die are tossed and the numbers on the sides that face upward are observed. ​(a) what is the p

robability that the sum of the numbers is less than 4
Mathematics
1 answer:
Tems11 [23]3 years ago
5 0

First of all, let's count how many events compose our sample space: since we are rolling two dice, and each of them has six sides, the sample space has 36 possible events, given by all couples (x,y), with x,y \in \{1,2,3,4,5,6\}

Then, we observe that none of the die can give 4 or more, otherwise the sum of the two dice would be at least 5.

So, we have the following possible outcomes:

Red die gives 1, green die gives 3

Both dice give 2

Red die gives 3, green die gives 1.

These are three events out of the 36 possible events, so their probability is

\cfrac{3}{36} = \cfrac{1}{12}

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Answer:

you bought 8 packs in total or four of each

Step-by-step explanation:

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3 years ago
Find the x- and y- intercepts of the line with the equation 3x+4y=-12
masya89 [10]
3x + 4y = -12

X - Intercept:    3x + 4y = -12
                      3x + 4(0) = -12
                           3x + 0 = -12
                                 3x = -12
                                  3       3
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                             (x, y) = (-4, 0)

Y - Intercept:   3x + 4y = 12
                     3(0) + 4y = 12
                         0 + 4y = 12
                               4y = 12
                                4      4
                                 y = 3
                           (x, y) = (0, 3)
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3 years ago
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dalvyx [7]

Answer:

(7+1÷5)−(4+5÷8) = 2 23/40 B

Step-by-step explanation:

7 1/5 - 4 5/8

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Hey, I think an image is needed to answer this question.
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the answer is 220 i calculated

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1 year ago
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