1. The amount of extension in an elastic spring varies directly as the weight hung on it. If a weight of 150 gm produces an exte
1 answer:
Answer:
900 g
Step-by-step explanation:
let e be extension and w be weight
given e varies directly as w then the equation relating them is
e = kw ← k is the constant of variation
to find k use the condition w = 150 , e = 2.9 , then
2.9 = 150k ( divide both sides by 150 )
= k , that is
k =
e = w ← equation of variation
when e = 17.4 , then
17.4 = w ( multiply both sides by 1500 )
26100 = 29w ( divide both sides by 29 )
900 = w
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Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then ≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2± where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704± ≈ -0.171 ±0.237 that is (−0.408, 0.066)