Answer:
We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2
Explanation:
Step 1: Data given
Number of moles K = 2.00 moles
Cl2 is in excess, so K is the limiting reactant
Step 2: The balanced equation
2K + Cl2 → 2KCl
Step 3: Calculate moles KCl
For 2 moles K we need 1 mol Cl2 to produce 2 moles KCl
We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2
Answer:
Explanation:
The charges are as follows:
since oxidation number of lead is 2 as indicated lead (II)nitrite. The number in parentheses indicates the oxidation number.
bears the charge -1.
As lead bears 2 positive charges so we need two nitrite ions to form lead (II) nitrite.
, it is a halogen and bears the charge -1.
, it is an alkali metal.
Since Bromide bears -1 charge and potassium bears +1 charge so we need only 1 ion of bromide and 1 ion of potassium to form potassium bromide.
Similarly, to form lead bromide we need 2 ions of bromide and 1 ion of lead, and to form potassium nitrite we need 1 nitrite ion and 1 potassium ion.
The final balanced equation is as follows, the various states of reactants and products are also written properly.