A truck driver travels from a distributor to a retailer every week. The driver records the distance that he is from the retailer
1 answer:
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9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
__
If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
Answer:Answer is option C : [ + 3x + 3 ] =0
Note: None of options matches with given question.
instead of "-3" , there should be "-".
Step-by-step explanation:
Note: None of options matches with given question.
instead of "-3" , there should be "".
Here, First thing you have to observe the nature of roots.
∴ x = -+
i and x = -
-
∴ [ x+(-
i) ][ x+(
+
i) ]=0
∴ [ + x(
+
i)+ x(
-
i) + (
-
i)(
+
i) ]=0
∴ [ +
x +
ix +
x -
ix + (3-
i)(3+
i) ] =0
∴ [ + 3x + (
-
i)(
+
i) ] =0
∴ [ + 3x +
- (
i)(
i) ] =0
∴ [ + 3x +
- (
)
] =0
∴ [ + 3x +
+ (
) ] =0
∴ [ + 3x +
] =0
∴ [ + 3x + 3 ] =0
Thus, Answer is option C : <em>[ + 3x + 3 ] =0 </em>