Consider the concepts of kinetic energy (KE) and gravitational potential energy (GPE) as you complete these questions. A ball is
1 answer:
Answer:
When the ball is held motionless above the floor, the ball possesses only GPE energy.If the ball is dropped, its GPE energy decreases as it falls.If the ball is dropped, its KE energy increases as it falls.
Explanation:
If the ball is held motionless, then its kinetic energy is equal to zero, since kinetic energy depends on the velocity. And the ball is held above the ground, which means it possesses gravitational potential energy.
If the ball is dropped, its height will decrease, therefore its gravitational potential energy will decrease. Along the way, the ball will be in free fall, and therefore its velocity will increase, hence its kinetic energy.
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Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.
<h3>Definition of current</h3>The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.
<h3>Definition of voltage</h3>The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.
<h3>Definition of resistance</h3>Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).
<h3>Ohm's law</h3>Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.
This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.
Mathematically, Ohm's law is expressed as:
Where:
- I is the current measured in amps (A).
- V the voltage measured in volts (V).
- R the resistance that is measured in ohms (Ω).
In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.
Replacing in the Ohm's Law:
Solving:
0.83 A× R= 120 V
<u><em>R= 144.58 Ω</em></u>
Finally, the resistance of the lightbulb is 144.58 Ω.
Learn more about Ohm's law:
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Answer:
The maximum height above the point of release is 11.653 m.
Explanation:
Given that,
Mass of block = 0.221 kg
Spring constant k = 5365 N/m
Distance x = 0.097 m
We need to calculate the height
Using stored energy in spring
...(I)
Using gravitational potential energy
....(II)
Using energy of conservation
Where, k = spring constant
m = mass of the block
x = distance
g = acceleration due to gravity
Put the value in the equation
Hence, The maximum height above the point of release is 11.653 m.
Answer:The frequency of the echo is slightly decreased
Explanation:
Given
speed of boat
cliff is away
when boat is still , suppose t is the time taken by the echo to reach observer on the boat
But as soon as boat starts moving the distance between cliff and boat decreasing and time for echo to reach observer also decreases
and we know
therefore frequency of the echo slightly decreased.