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aev [14]
3 years ago
7

Five less than the product of 14 and carlos's age use the variable c to represent carlos's age

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0
" the product " means multiply

14c - 5 <== ur expression
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Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3
Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

y = 6

Substituting the values into equation (1) and solve c, we have:

60 = c * 5 * 6

60 = c * 30

c = 60 / 30

c = 2

Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0
3 years ago
Rewrite this decimal 4.5 as a mixed fraction in its lowest term. ​
Crazy boy [7]

Answer:

4.5=4 and 1/2

Step-by-step explanation:

4 0
3 years ago
What is an imaginary number?
trapecia [35]

An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by it's property i² = −1. The square of an imaginary number bi is −b². For example, 5i is an imaginary number, and it's square is −25.

8 0
3 years ago
I need help please ASAP full points
kotegsom [21]

The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole

In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.

We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24

Then, we just plug these values back into the above equation:

96 = 0.24w

Divide both sides by 0.24 to get w on it's own, and you have your answer!

400 = w

Therefore, the memory card can hold up to 400 pictures.


Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.

4 0
3 years ago
How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?
Phantasy [73]
35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35

One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
5 0
4 years ago
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