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andrew11 [14]
3 years ago
5

Which equation is correct? arccsc(x)=1/cos(x)

Mathematics
1 answer:
viva [34]3 years ago
7 0

Answer:

arccsc(x)=1/cos(x)

Step-by-step explanation:

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What is 30 / 3what is 30 / 3 ​
mojhsa [17]

30/3 = 10

hope that helps^^

6 0
3 years ago
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What number has the absolute value of 16​
german
The Answer is -16

I hope this helps
4 0
3 years ago
Clara has a lawn in front of her house as mapped on the coordinate plane. She wants to plant a bed of flowers between the points
Hunter-Best [27]

Answer:

<em>Look Below In the Explanation</em>

Step-by-step explanation:

Point P has coordinates of (4,4) and point Q has coordinates of (4,-4).

Since both points have the same x-coordinates we can subtract point Q's y-coordinate from point P's y-coordinate.

I will set the equation up and try and figure this part by yourself. I hope you learned what to do from previous questions that are very similar to this that I answered.

4 - ( -4) = length of the bed of flowers

Hope that helps and maybe earns a brainliest!

Have a splendid day! :^)

3 0
2 years ago
Read 2 more answers
Previous
Natali5045456 [20]

Answer: y = 5d + 7 / c - 3

Step-by-step explanation:

Step 1: Add -3y to both sides

cy - 7 + -3y = 5d + 3y + -3y

= cy - 3y - 7 = 5d

Step 2: Now, add 7 on both sides

cy - 3y - 7 +7 = 5d +7

= cy - 3y = 5d +7

Step 3: Factor out y

y(c - 3) = 5d + 7

Step 4: Divide both sides by c-3

y(c - 3) / c - 3 = 5d+7 / c-3

Your answer for this should be

y = 5d + 7 / c - 3

Hope this helped!

3 0
3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.
Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0
2 years ago
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