Answer:
option (b) 0.0228
Step-by-step explanation:
Data provided in the question:
Sample size, n = 100
Sample mean, μ = $20
Standard deviation, s = $5
Confidence interval = between $19 and $21
Now,
Confidence interval = μ ± 
thus,
Upper limit of the Confidence interval = μ +
or
$21 = $20 + 
or
z = 2
Now,
P(z = 2) = 0.02275 [From standard z vs p value table]
or
P(z = 2) ≈ 0.0228
Hence,
the correct answer is option (b) 0.0228
Need drawing not sure where m is
Hello! This is actually pretty easy to solve, all you have to do is subtract 28.65 from 24.25 So when you subtract 5 from 5, you get zero. When you subtract 6 from 2, you get 4. When you subtract 8 from 4, you get 4, and when you subtract 2 from 2 you get zero. So all you do is take out the zeros and put the decimal point in the same place it was in before, and this should leave you with your answer!
I hope this helped!
I am, yours most sincerely,
SuperHelperThingy
