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shtirl [24]
3 years ago
11

900 students attend Ridgewood Junior High School. 5% of students bring their lunch to school everyday. How many students brought

their lunch to school on Thursday?
Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

180 students brought their lunch to school on Thursday

Step-by-step explanation:

We are told that out of 900, 5% of the students brought their lunch to school everyday

So the number that brought their lunch on Thursday will be;

5% of 900

= 5/100 * 900 = 180

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If f(x) = 3x -2 and g(x).= 4x + 1.<br> what is the sum of f(2) and g(-3)
ira [324]

Answer:

The sum of f(2) and g(-3) is -7.

Step-by-step explanation:

f(x) = 3x - 2

f(2) = 3(2)-2

f(2) = 6 -2 = 4

g(x) = 4x + 1

g(-3) = 4(-3) +1

g(-3) = -12 + 1 = -11

f(2) + g(-3) = 4 + (-11)

f(2) + g(-3) = -7

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3 years ago
123556 cube root pls ​
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It is irrational, which means it goes on forever.                          ✧          ☆    

Step-by-step explanation:                                                                      ✺    ✹

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4 0
3 years ago
For 23-25, use the table.
alexandr402 [8]
Jon and Gina are different we’re opposite
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3 years ago
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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
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