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Tresset [83]
4 years ago
6

Hor and Hulk are fighting eachother, back and forth in a straight line in the master's colosseum. Hulk punches thor into a wall

30 meters away from the start. Thor then hit's hulk with a hammer, hurling Hulk 45 meters back from the wall. This all happens in the course of 3 seconds. What is the speed of their fight across the arena?
a. 25 m/s
b. 10 m/s forward from Hulk and Thor's starting point.
c. 5 m/s backwards from hulk's starting point
d. 5 m/s
Physics
1 answer:
Nitella [24]4 years ago
6 0

Answer:

A

Explanation:

cant be c because its asking for speed and speed doesnt have direction

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Mercury has an average disease to the sun of 0.39 AU. In two or more complete sentences, explain how to calculate the orbital pe
alukav5142 [94]

Answer: 88 Earth days

Explanation:

According to the Kepler Third  Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

<em />

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit:

T^{2}=a^{3} (1)

If we assume the orbit is circular and apply Newton's law of motion and the Universal Law of Gravity we have:

T^{2}=\frac{4\pi^{2}}{GM}a^{3} (2)

Where M is the mass of the massive object and G is the universal gravitation constant. If we assume M constant and larger enough to consider G  really small, we can write a general form of this law:

MT^{2}=a^{3} (3)

Where T is in units of Earth years,  a is in AU (<u>1 Astronomical Unit is the average distane between the Earth and the Sun)</u> and  M is the mass of the central object  in units of the mass of the Sun.

This means when we are making calculations with planets in our solar system  M=1.

Hnece, in the case of Mercury:

(1)T^{2}=(0.39 AU)^{3} (4)

Isolating T:

T=\sqrt{(0.39 AU)^{3}} (5)

T=0.243 Earth-years \frac{365 days}{1 Earth-year}=88.6 days \approx 88 days (6)

This means the period of Mercury is 88 days.

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