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postnew [5]
3 years ago
10

what is the total magnification of a specimen viewed with a 10x ocular lens and a 45x objective lens?

Physics
1 answer:
grigory [225]3 years ago
8 0

Answer:

450

Explanation:

total magnification = eyepiece lens x objective lens

10 x 45 = 450

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The mass of the motorbike and rider is 286 kg. Calculate the acceleration of the motorbike at this moment in time.
Aleks04 [339]

Answer:

a=4.03\ m/s^2

Explanation:

Given that,

The mass of the motorbike and rider is 286 kg.

We need to find the acceleration of the motorbike at this moment in time.

Net force acting on the bike is given by :

F = 2000 N - 845 N = 1155 N

Let a be the acceleration of the motorbike. So,

a=\dfrac{F}{m}\\\\a=\dfrac{1155}{286}\\\\a=4.03\ m/s^2

So, the acceleration of the motorbike is 4.03\ m/s^2.

7 0
3 years ago
object of mass m=2.6 kg is dropped from rest at a height of h above a massless spring with spring constant k=494.3 N/m that is i
tekilochka [14]

Answer:

3.56 m

Explanation:

As the object falls from height h, and then compresses the spring a distance of 0.66m, its initial potential energy is converted into elastics energy of the spring.  

Let g = 9.81m/s2. Knowing that the total change in potential height is h + d, we have the following equation

E_p = E_s

mg(h + d) = kd^2/2

2.6*9.81(h + 0.66) = 494.3*0.66^2/2

h + 0.66 = 4.22

h = 4.22 - 0.66 = 3.56 m

3 0
3 years ago
I have a few questions. How would density change if volume is not calculated correctly?
VikaD [51]
Density equals mass divided by volume so the ball the higher amount of mass has more density than the ball with less mass has less density. (The golf ball has more density than the ping pong ball)
7 0
3 years ago
Please help me. Thanks
belka [17]
Both mass and weight
4 0
3 years ago
Read 2 more answers
A lawyer drives from her​ home, located 1 mile east and 8 miles north of the town​ courthouse, to her​ office, located 4 miles w
givi [52]

Answer:

d = 13 miles

Explanation:

Lets say the position of court house is origin in this case

her office is located at 4 miles west and 4 miles south of court house

so here we have coordinate of the office with respect to court house is given as

r_1 = (-4\hat i - 4\hat j)

now the position of her home is located at 1 miles east and 8 miles north of the court house

so the coordinates of her home is given as

r_2 = (1\hat i + 8 \hat j)

now the change in the position is given as the distance between office and home

d = r_2 - r_1

d = 5 \hat i + 12 \hat j

d = \sqrt{5^2 + 12^2} = 13 miles

4 0
4 years ago
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