Answer: the answer is d
Step-by-step explanation:
Answer:
7 and 6 respectively
Step-by-step explanation:
Firstly, we have to solve the equations simultaneously.
2x + 7p = 56
3x - 11p = -45
Multiply equation I by 3 and ii by 2
6x +21p = 168
6x - 22p = -90
Subtract the second from first to yield:
43p = 258
p = 6
Insert this in equation 1 where we have 2x + 7p = 56
2x + 7(6) =56
2x + 42 = 56
2x = 14 and x = 7
The equilibrium price is 6 and the equilibrium quantity is 7
-3x-4<19
19+4=23
3x<23
÷3 ÷3
×= > 23/3 or 7.6^87
The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.
<h3>What three numbers should be placed between 12 and 60?</h3>
It follows from the task content that the first and last numbers are; 12 and 60 respectively.
Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,
It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.
Read more on common difference;
brainly.com/question/19601308
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