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Nimfa-mama [501]
3 years ago
7

As much as 25 percent of the fruits and vegetables grown in Chinese agricultural regions rot before they can be transported the

long distances to market. which of the following is a smaller, more manageable problem that contributes to this complex problem?
A. Conserving Earth's limited fossil fuel reserves
B. Reducing global emissions of greenhouse gases
C. Developing effective methods of food preservation
D. Preventing extinction of endangered species
Chemistry
1 answer:
gulaghasi [49]3 years ago
7 0

C. Developing effective methods of food preservation

Explanation:

The development of effective methods of food preservation is a much more smaller and manageable problem that contributes to the complex problem.

The percentage of food rotting is not as a result of lack of an effective preservation technique as highlighted in the passage. It is due to the long distances of agricultural area from where the farms are located.

  • To cut the loss, efficient and rapid transportation techniques needs to be put in place to carry the fruits and vegetables to the area where they are needed.
  • This is the most complex problem that if solved can peg back food rot.
  • Additional measures should be put in place to preserve the food.

Other options does not address the subject matter  

learn more:

Preservation brainly.com/question/4853419

#learnwithBrainly

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If nitrogen (N) has 2 naturally occurring isotopes, nitrogen-14 (78.3%) and nitrogen-16 (21.7%), what is its average r.a.m.?
leva [86]

Answer:

14.434 r.a.m.

Explanation:

  • The atomic mass of an element is a weighted average of its isotopes in which the sum of the abundance of each isotope is equal to 1 or 100%.

∵ The atomic mass of N = ∑(atomic mass of each isotope)(its abundance)

∴ The atomic mass of N = (atomic mass of N-14)(abundance of N-14) + (atomic mass of N-16)(abundance of N-16)

atomic mass of N-14 = 14.0 r.a.m, abundance of N-14 = percent of N-14/100 = 78.3/100 = 0.783.

atomic mass of N-16 = 16.0 r.a.m, abundance of N-16 = percent of N-16/100 = 21.7/100 = 0.217.

∴ The atomic mass of N = (atomic mass of N-14)(abundance of N-14) + (atomic mass of N-16)(abundance of N-16) = (14.0 r.a.m)(0.783) + (16.0 r.a.m)(0.217) = 14.434 r.a.m.

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3 years ago
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Answer:

15m

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vi = 0

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10^2 = 0 + 2(-9.8)(x2-x1) = -5.1

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3 0
2 years ago
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