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Nimfa-mama [501]
3 years ago
7

As much as 25 percent of the fruits and vegetables grown in Chinese agricultural regions rot before they can be transported the

long distances to market. which of the following is a smaller, more manageable problem that contributes to this complex problem?
A. Conserving Earth's limited fossil fuel reserves
B. Reducing global emissions of greenhouse gases
C. Developing effective methods of food preservation
D. Preventing extinction of endangered species
Chemistry
1 answer:
gulaghasi [49]3 years ago
7 0

C. Developing effective methods of food preservation

Explanation:

The development of effective methods of food preservation is a much more smaller and manageable problem that contributes to the complex problem.

The percentage of food rotting is not as a result of lack of an effective preservation technique as highlighted in the passage. It is due to the long distances of agricultural area from where the farms are located.

  • To cut the loss, efficient and rapid transportation techniques needs to be put in place to carry the fruits and vegetables to the area where they are needed.
  • This is the most complex problem that if solved can peg back food rot.
  • Additional measures should be put in place to preserve the food.

Other options does not address the subject matter  

learn more:

Preservation brainly.com/question/4853419

#learnwithBrainly

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3) In the reaction below, how many grams of carbon dioxide are produced when iron III
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<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
  • Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

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<h3>Step 2: Calculate the number of moles of CO₂</h3>
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Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

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Hence, the mass of CO₂ produced from the reaction is 132.03 g

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