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Softa [21]
3 years ago
12

3. Antony and Cleopatra are 100 miles apart . To meet at a planned location , Antony travels at 12 mph and Cleopatra travels at

8 mph. How far must Antony travel if they leave at the same time?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

60 miles

Step-by-step explanation:

Distance apart = 100

Rate of travel. :

Anthony = 12 mph

Cleopafda = 8 mph

Using the relation :

Speed = distance / time

Distance = speed * time

If they leave at the same time, travel time Can be represented as x

Anthony's distance + Cleopafda distance = total distance

12x +. 8x = 100

20x = 100

x = 5

Hence, they both traveled for 5 hours before meeting.

Distance covered by Anthony :

Speed * time

12 mph * 5h = 60 miles

Anthony must travel. For 60 miles.

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3 years ago
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<em>3</em><em>5</em><em> </em><em>h</em><em>o</em><em>t</em><em> </em><em>d</em><em>o</em><em>g</em><em>s</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>5</em><em>2</em><em> </em><em>s</em><em>o</em><em>d</em><em>a</em><em>s</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>s</em><em>o</em><em>l</em><em>d</em><em>.</em><em> </em>

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