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Evgesh-ka [11]
2 years ago
12

HELP PLEASE WILL MARK BRANIEST IF right

Mathematics
1 answer:
Nataliya [291]2 years ago
4 0

Answer:

f(g(5)) = 5

g(f(4)) = 0

f(f(6))=1

g(g(9)) = 0

Step-by-step explanation:

Given

The attached table of values

Solving (a): f(g(5))

First, we solve for g(5)

g(5) = 7

So:

f(g(5)) = f(7)

Next, we solve for f(7).

From the table

f(7) = 5

So:

f(g(5)) = 5

Solving (b): g(f(4))

First, we solve for f(4)

f(4) = 6

So:

g(f(4)) = g(6)

Next, we solve for g(6).

From the table

g(6) = 0

So:

g(f(4)) = 0

Solving (c): f(f(6))

First, we solve for f(6)

f(6) = 8

So:

f(f(6)) = f(8)

Next, we solve for f(8).

From the table

f(8) = 1

So:

f(f(6))=1

Solving (d): g(g(9))

First, we solve for g(9)

g(9) = 6

So:

g(g(9)) = g(6)

Next, we solve for g(6).

From the table

g(6) = 0

So:

g(g(9)) = 0

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Factor the expression completely.<br> 625x4 - 256y4
scoundrel [369]

<u>Answer:</u>

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<u></u>

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<u> </u>

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<u> </u>

<u>Proof :  (A+B) • (A-B) = </u>

<u>         A2 - AB + BA - B2 = </u>

<u>         A2 - AB + AB - B2 = </u>

<u>         A2 - B2Note :  AB = BA is the commutative property of multiplication. </u>

<u> </u>

<u>Note :  - AB + AB equals zero and is therefore eliminated from the expression. </u>

<u> </u>

<u>Check :  625  is the square of  25  </u>

<u>Check : 256 is the square of 16 </u>

<u>Check :  x4  is the square of  x2  </u>

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<u>Check :  y4  is the square of  y2  </u>

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<u>Factorization is :       (25x2 + 16y2)  •  (25x2 - 16y2)  3.2      Factoring:  25x2 - 16y2  </u>

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<u>Check :  25  is the square of  5  </u>

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3 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
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3 years ago
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liq [111]

Answer:

\overline {PM} \cong \overline {ON} because they are opposite sides of a parallelogram.

Step-by-step explanation:

First of all, let us have a look at the definition of a parallelogram.

<em>A parallelogram is a closed 4 sided figure (i.e. a quadrilateral) made up with two pairs of straight lines such that the two pairs are parallel and equal to each other.</em>

<em></em>

For example, let us consider a quadrilateral ABCD as attached in the diagram in answer area.

The two pair of lines are:

AB,  DC and BC, AD

For ABCD to be a parallelogram, the lines

AB and DC must be parallel to each other and AB = DC

AND

BC and AD must be parallel to each other and BC = DA

------------------------------

In the given question, we are given that the quadrilateral MNOP is a parallelogram.

The two pairs opposite lines are OP, NM and PM, ON.

As per the definition of a parallelogram,

OP and NM must be <em>parallel and equal </em>to each other.

AND

PM and ON must be <em>parallel and equal </em>to each other.

\therefore \overline {PM} \cong \overline {ON}.

Hence proved.

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3 years ago
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maria [59]
They can because of zero property. If we set them equal to zero we get their roots which is 3 and -2. This is the same on the x axis which is goes through. We can mark these points.
4 0
3 years ago
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polet [3.4K]

Answer:

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Step-by-step explanation:

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\boxed{\green{=  \frac{1}{15} x}}

4 0
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