When the first reaction equation is:
AgI(S) ↔ Ag+(Aq) + I-(Aq)
So, the Ksp expression = [Ag+][I-]
∴Ksp = [Ag+][I-] = 8.3 x 10^-17
Then the second reaction equation is:
Ag+(aq) + 2NH3(aq) ↔ Ag(NH3)2+
So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2
∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7
by combining the two equations and solve for Ag+:
and by using ICE table:
AgI(aq) + 2NH3 ↔ Ag(NH3)2+ + I-
initial 2.5 0 0
change -2X +X +X
Equ (2.5-2X) X X
so K = [Ag(NH3)2+] [I-] / [NH3]^2
Kf * Ksp = X^2 / (2.5-2X)
8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X
∴ X = 5.9 x 10^-5
∴ the solubility of AgI = X = 5.9 x 10^-5 M
A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.
Explanation:
The answer is 0.5 moles of gold
Answer:
V₂ =279.4 cm³
Explanation:
Given data:
Initial volume = 260 cm³
Initial temperature = 22.0°C
Final temperature = 44.0°C
Final volume = ?
Solution;
22.0°C (22+ 273 = 295k)
44.0°C(44+273 = 317k)
Formula:
According to Charles's law
V₁/T₁ = V₂/T₂
Now we will put the values in formula:
V₂ = V₁×T₂ / T₁
V₂ = 260 cm³ × 317k / 295k
V₂ = 82420 cm³. k / 295k
V₂ =279.4 cm³
Answer:
protons and neutrons located within the nucleus, with electrons in orbitals surrounding the nucleus.