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2 years ago

Case #4

Chemistry

1 answer:

stiv31 [10]2 years ago

3 0

Answer: 1.) His action is not justified because he could have done something else like talking with someone.

2.) Some of the negative consequences could be Mr. King could lose his job or worse not be able to teach again.

3.) Some other options were having him retake the test or talking to the head of the school, or many other things.

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Which type of weathering occurs most frequently at high elevations, and can bring mountains down to sea level over time?

gladu [14]

I pretty sure it’s rainfall

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3 years ago

Which compound is responsible for the smell that is associated with the decomposition of dead animals?

CaHeK987 [17]

the results from the breakdown of proteins and amino acids causing a foul smell

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3 years ago

Help in chem please!!!!!!

IgorLugansk [536]

This is a one-step unit analysis problem. Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

$1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}$

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

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3 years ago

A gas has a volume of 240.0mL at 25C and 600.0 mmHg. Calculate it's volume at STP

atroni [7]

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6 0

3 years ago

You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea

Elden [556K]

Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

Density of salt water = 1.02 g/mL

Calculating the volume from mass and density:

$182g*\frac{mL}{1.02g} =178mL$

Converting the volume from mL to cubic cm:

$178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}$

Assuming the balloon to be a sphere,

Volume of the sphere = $\frac{4}{3}$ π $r^{3}$

$178 cm^{3} = \frac{4}{3}(\frac{22}{7})r^{3}$

r = 3.49 cm

Radius of the balloon = 3.49 cm

Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm

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3 years ago