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patriot [66]
4 years ago
14

On increasing the concentration of reactants in reversible reaction,then eqillibrium constant will. a) Depend on the concentrati

on. b) increase. c) unchanged d) decrease
Chemistry
1 answer:
fredd [130]4 years ago
4 0

Answer:

c) Unchanged

Explanation:

The reaction mixture will always shift such that equilibrium is achieved !!!Even if concentration is changed , the system will move towards less stress and this is when equilibrium is achieved hence the system will always tend to proportions of reactants and products which leave the system with the least potential energy hence the equilibrium constant unchanged

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Gallium (Ga) consists of two naturally occurring isotopes with masses of 68.926 and 70.925 amu. (a) How many protons and neutron
pav-90 [236]

Answer:

neutrons_{Ga-69}=38\\\\neutrons_{Ga-71}=40

Explanation:

Hello!

In this case, since isotopes of the same element have the same number of protons and electrons but different atomic mass, we can compute the number of neutrons by subtracting the number of protons to the atomic mass of the isotope; thus, for Ga-69 and Ga-71 (rounded up to whole numbers), we obtain:

neutrons_{Ga-69}=69-31=38\\\\neutrons_{Ga-71}=71-31=40

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8 0
3 years ago
At what temperature are the liquid and the vapour of Bromine in equilibrium (e.g. boiling point)?
irina [24]

Explanation:

Boiling point is defined as the point at which liquid state and vapor state of a substance are existing in equilibrium.

Equilibrium is defined as the state in which rate of forward and rate of backward reaction are equal to each other.

For example, Br(l) \rightleftharpoons Br(g)

So, when we boil bromine which is present in liquid state then at the boiling point its vapors will exist in equilibrium. And unless all the liquid state of bromine will not convert into vapors its temperature will not change.

Therefore, we can conclude that at boiling point the liquid and the vapur of Bromine are in equilibrium.

7 0
3 years ago
Plsss help me!!! ASAP!!!
Arisa [49]

Answer:

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8 0
3 years ago
(LO 3N, 4G, 4O) Aluminum sulfate is also involved in dying fabrics. The gelatinous precipitate formed in the reaction with dilut
brilliants [131]

9.4 × 10⁻³ mg (0.73 mmoles) of Al(OH)₃ is formed

Explanation:

We have the following chemical reaction:

Al₂(SO₄)₃(aq) + 6 NaOH(aq) → 2 Al(OH)₃(s) + 3 Na₂SO₄(aq)

The precipitate mentioned by the problem is aluminium hydroxide Al(OH)₃.

Now to determine the number of moles of sodium hydroxide NaOH we use the following formula:

molar concentration =  number of moles / volume

number of moles = molar concentration × volume

number of moles of NaOH = 0.088 M × 25 mL = 2.2 mmoles

number of moles of Al₂(SO₄)₃ = 5.6 × 10⁻³ moles = 5.6 mmoles (found in the  problem text)

We see from the chemical reaction that 1 mole of Al₂(SO₄)₃ requires 6 moles of NaOH so 5.6 mmoles of Al₂(SO₄)₃ would require 6 times more NaOH which is 33.6 mmoles and we have only 2.2 mmoles. The limiting reactant will be NaOH.

Now we devise the following reasoning:

if        6 mmoles of NaOH produces 2 mmoles of Al(OH)₃

then  2.2 mmoles of NaOH produces X mmoles of Al(OH)₃

X = (2.2 × 2) / 6 = 0.73 mmoles of Al(OH)₃

mass of Al(OH)₃ = number of moles / molecular weight

mass of Al(OH)₃ = 0.73 / 78

mass of Al(OH)₃ =  9.4 × 10⁻³ mg

Learn more:

precipitation reaction

brainly.com/question/10400269

7 0
3 years ago
What happens if you add more solute to a unsaturated solution
Fiesta28 [93]

The solute normally doesn't dissolve and sinks to the bottom of the container. However, some saturated solutions can become super-saturated for a given temperature and pressure, by altering the conditions without allowing solute to precipitate.

6 0
4 years ago
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