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Marizza181 [45]
2 years ago
6

What's the momentum of a 3.5-kg boulder rolling downhill at 5 m/s? A. 17.5 km·m/s B. 70 kg·m/s C. 8.5 kg·m/s D. 14.3 kg·m/s

Chemistry
2 answers:
swat322 years ago
7 0

Hey There!:


p = m * V


p = 3.5 * 5


p = 17.5 Km.m/s


Answer A


hope this helps!

Vladimir79 [104]2 years ago
5 0

Answer : The correct option is, (A) 17.5\text{ Kg }m/s

Solution : Given,

Mass of an object = 3.5 Kg

Velocity of an object = 5 m/s

Momentum : Momentum is equal to the product of mass of an object and the velocity of an object.

Formula used :

p=m\times v

where,

p = momentum of an object

m = mass of an object

v = velocity of an object

Now put all the given values in this formula, we get the value of momentum of an object.

p=(3.5Kg)\times (5m/s)=17.5\text{ Kg }m/s

Therefore, the momentum of an object is, 17.5\text{ Kg }m/s

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Answer:

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Explanation:

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here's the balanced chemical equation for the above reaction : -

CaCl2 + Na2CO3 =》CaCO3 + 2 NaCl

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Why is sucrose insoluble in dichloromethane?
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3 years ago
A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r
Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 1\times 10^{-2}mol/L.s

t = time taken  = ?

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Putting values in above equation, we get:

1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)

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