What's the momentum of a 3.5-kg boulder rolling downhill at 5 m/s? A. 17.5 km·m/s B. 70 kg·m/s C. 8.5 kg·m/s D. 14.3 kg·m/s
2 answers:
Answer : The correct option is, (A)
Solution : Given,
Mass of an object = 3.5 Kg
Velocity of an object = 5 m/s
Momentum : Momentum is equal to the product of mass of an object and the velocity of an object.
Formula used :
where,
p = momentum of an object
m = mass of an object
v = velocity of an object
Now put all the given values in this formula, we get the value of momentum of an object.
Therefore, the momentum of an object is,
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The answer for the following question is mentioned below.
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Explanation:
Given:
Pressure of gas (P) = 1.2 atm
Volume of a gas (V) = 50.0 liters
Temperature (T) =650 K
To calculate:
no of moles present in the gas (n)
We know;
According to the ideal gas equation;
We know;
<u>P × V = n × R × T </u>
where,
P represents pressure of the gas
V represents volume of the gas
n represents no of the moles of a gas
R represents the universal gas constant
where the value of R is 0.0821 L atm mole^{-1} K^-1
T represents the temperature of the gas
As we have to calculate the no of moles of the gas;
n =
n = \frac{1.2*50.0}{0.0821*650}
n = \frac{60}{53.365}
n = 1.12 moles
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Answer:
B) 0.025
Explanation:
Solution of the problem is in picture attached,
