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3 years ago

What is the specific heat for the steel wire

Chemistry

1 answer:

olganol [36]3 years ago

8 0

I think that the answer is 0.49

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For the following reaction, 22.6 grams of nitrogen monoxide are allowed to react with 4.64 grams of hydrogen gas . nitrogen mono

antiseptic1488 [7]

Answer:

- 10.5 g of N₂

- Limiting reagent: NO

- 3.13 g of H₂ remains

Explanation:

First of all we state the reaction: 2NO(g) + 2H₂(g) → 2H₂O(l) + N₂(g)

We need to find out the limiting reactant and the excess reagent

Ratio in the reactants is 2:2. Let's convert the mass to moles:

22.6 g / 30 g/mol = 0.753 moles of NO

4.64 g / 2 g/mol = 2.32 moles of H₂

Certainly the limiting reagent is the NO and the excess reactant is the hydrogen:

- For 0.753 moles of NO, we need 0.753 moles of H₂ (we have 2.32 moles)

- For 2.32 moles of H₂, we need 2.32 moles of NO (and we don't have enough NO, because we only have 0.753 moles)

As the H₂ is the excess reagent, some moles still remains after the reaction is complete → 2.32 mol - 0.753 mol = 1.567 moles

We convert the moles to mass: 1.567 mol . 2g /1mol = 3.13 g of H₂ remains

As the NO is the limiting reagent, we can work with the equation:

We propose this rule of three: 2 moles of NO can produce 1 mol of N₂

Then, 0.753 moles of NO must produce (0.753 . 1) /2 = 0.376 moles of N₂

We convert the moles to mass 0.376 mol . 28 g / 1 mol = 10.5 g

3 0

3 years ago

How many significant figures are in this number? 22.0 grams

Inga [223]

Answer:

Hey there!

22.0 has three significant figures.

Let me know if this helps :)

6 0

3 years ago

What is the MSDS? Why is it important? *

Pavlova-9 [17]

Answer:

Hey there!

A MSDS is a Material Safety Data Sheet, and can be used to provide detailed and comprehensive information about the hazards of a certain product, such as medicine or chemicals.

Let me know if this helps :)

6 0

3 years ago

Use the equation below to determine the maximum number of grams of PH3 that can be formed when 8.2 g of phosphorus reacts with 4

olga55 [171]

did you get the answer? pls

3 0

3 years ago

How many excited electron in the atom with an electron configuration of [kr]5s24d55p6 ?

IRISSAK [1]

The ground-state electronic configuration follows the order of orbitals as shown in the first picture. So, we can deduce that the electronic configuration given is in order. However, each orbital must have a maximum number of electrons to be filled before it can move on to the next orbital. Since the d orbital must hold 10 electrons, that means that it should have held 5 electrons more. The missing 5 electrons were excited to the next 5p orbital. <em>Thus, there are 5 excited electrons.</em>

4 0

3 years ago