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sattari [20]
3 years ago
5

Describe the four types of fronts and the weather associated with each.

Chemistry
1 answer:
FrozenT [24]3 years ago
3 0

The Four type is

Cold front

Warm front

Stationary front

Occluded front

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When do plants use the process of cellular respiration
d1i1m1o1n [39]

Answer:

So the answer is every day

Explanation:

Plants respire at all times of the day and night because their cells need a constant energy source to stay alive.

8 0
3 years ago
Convert 678.92 cm into meters​
Anastaziya [24]

Answer:6.7892 meters

Explanation:

4 0
3 years ago
A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L
PtichkaEL [24]

Answer:

  9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

T₁ = 25°C = 25 + 273.15 K = 298.15 K

 P₁ = 98.7 Kpa

 T₂ = 20°C = 20 + 273.15 K = 293.15 K

  P₂ = 102.7 KPa

  V₂ = ?

2) Formula:

Used combined law of gases:

  PV / T = constant

  P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

  V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

7 0
2 years ago
Compare and contrast the ease at which molecules are able to move relative to each other in the three states of matter
ANTONII [103]
The arrangement of molecules within the 3 phases of matter are shown in the picture. 

For the solid, the molecules are packed closely together. They don't have much space to move, so they just practically vibrate. For the liquid, the molecules are relatively farther from each other. The liquid molecules can flow freely but not as much as the gases. In the gases, the molecules are very far from each other. They are very sensitive to slight changes of pressure, volume and temperature.

5 0
3 years ago
4. An 82 kg hiker climbs Mt. Humphrey near Flagstaff. During a two hour period, the hiker's
bazaltina [42]

Answer:

\Delta E = 434253.96\,J, \Delta P = 60.313\,W

Explanation:

The change in energy is given by the change in gravitational potential energy:

\Delta E = m\cdot g \cdot \Delta h

\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)

\Delta E = 434253.96\,J

The average rate of change in terms of time is approximately this:

\Delta P = \frac{\Delta E}{\Delta t}

\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}

\Delta P = 60.313\,W

8 0
3 years ago
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