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3 years ago

-3/5x=42 help pleeeeeeeeeeeeeaaaaaaaaaaaaaaaaaaasssssssssssssssseeeeeeeeeeeee

Mathematics

2 answers:

Fynjy0 [20]3 years ago

5 0

Answer:

X = -70

Step-by-step explanation:

Multiply both sides of the equation by

screen shot has my step by step

Hope it was helpful

Zanzabum3 years ago

3 0

Answer:

x=-70

Step-by-step explanation:

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How did President George W. Bush respond to the terrorist attacks of September 11, 2001?

Fynjy0 [20]

you answer is C

so the united states invasion of afghanistan occurred after the September 11 attacks in late 2001, supported by close US allies. The conflict is also known as the US war in Afghanistan. the goal was to dismantle al-Qaeda and deny it a safe base of operations in Afghanistan by removing the Taliban from power.

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3 years ago

What are the roots of -12x2 + 11x − 3 = 0?

boyakko [2]

This equation is not factor-able, so we can use the quadratic formula.
x=(-11+square root(11^2-4(-12*-3)))/(2*-12)
x=(-11+square root(-23))/(-24)
Since we have the square root of a negative in this equation, there are no real roots for the quadratic.

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3 years ago

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10 points. See picture, find area of shaded region. please answer in a way that I can fill out the blanks at the bottom

matrenka [14]

I'm sorry I can't answer this but the triangle looks like it's wearing a thong

4 0

3 years ago

Can anyone help me please

kicyunya [14]

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3 0

3 years ago

Please solve, answer choices included.

qaws [65]

4. To solve this problem, we divide the two expressions step by step:

$\frac{x+2}{x-1}* \frac{x^{2}+4x-5 }{x+4}$
Here we have inverted the second term since division is just multiplying the inverse of the term.

$\frac{x+2}{x-1}* \frac{(x+5)(x-1)}{x+4}$
In this step we factor out the quadratic equation.

$\frac{x+2}{1}* \frac{(x+5)}{x+4}$
Then, we cancel out the like term which is x-1.

We then solve for the final combined expression:
$\frac{(x+2)(x+5)}{(x+4)}$

For the restrictions, we just need to prevent the denominators of the two original terms to reach zero since this would make the expression undefined:

$x-1\neq0$
$x+5\neq0$
$x+4\neq0$

Therefore, x should not be equal to 1, -5, or -4.

Comparing these to the choices, we can tell the correct answer.

ANSWER: $\frac{(x+2)(x+5)}{(x+4)}$ ; $x\neq1,-4,-5$

5. To get the ratio of the volume of the candle to its surface area, we simply divide the two terms with the volume on the numerator and the surface area on the denominator:

$\frac{ \frac{1}{3} \pi r^{2}h }{ \pi r^{2}+ \pi r \sqrt{ r^{2} +h^{2} } }$

We can simplify this expression by factoring out the denominator and cancelling like terms.

$\frac{ \frac{1}{3} \pi r^{2}h }{ \pi r(r+ \sqrt{ r^{2} +h^{2} } )}$
$\frac{ rh }{ 3(r+ \sqrt{ r^{2} +h^{2} } )}$
$\frac{ rh }{ 3r+ 3\sqrt{ r^{2} +h^{2} } }$

We then rationalize the denominator:

$\frac{rh}{3r+3 \sqrt{ r^{2} + h^{2} }} * \frac{3r-3 \sqrt{ r^{2} + h^{2} }}{3r-3 \sqrt{ r^{2} + h^{2} }}$
$\frac{rh(3r-3 \sqrt{ r^{2} + h^{2} })}{(3r)^{2}-(3 \sqrt{ r^{2} + h^{2} })^{2}}}=\frac{3 r^{2}h -3rh \sqrt{ r^{2} + h^{2} }}{9r^{2} -9 (r^{2} + h^{2} )}=\frac{3rh(r -\sqrt{ r^{2} + h^{2} })}{9[r^{2} -(r^{2} + h^{2} )]}=\frac{rh(r -\sqrt{ r^{2} + h^{2} })}{3[r^{2} -(r^{2} + h^{2} )]}$

Since the height is equal to the length of the radius, we can replace h with r and further simplify the expression:

$\frac{r*r(r -\sqrt{ r^{2} + r^{2} })}{3[r^{2} -(r^{2} + r^{2} )]}=\frac{ r^{2} (r -\sqrt{2 r^{2} })}{3[r^{2} -(2r^{2} )]}=\frac{ r^{2} (r -r\sqrt{2 })}{-3r^{2} }=\frac{r -r\sqrt{2 }}{-3 }=\frac{r(1 -\sqrt{2 })}{-3 }$

By examining the choices, we can see one option similar to the answer.

ANSWER: $\frac{r(1 -\sqrt{2 })}{-3 }$

8 0

3 years ago