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Georgia [21]
3 years ago
12

-3/5x=42 help pleeeeeeeeeeeeeaaaaaaaaaaaaaaaaaaasssssssssssssssseeeeeeeeeeeee

Mathematics
2 answers:
Fynjy0 [20]3 years ago
5 0

Answer:

X = -70

Step-by-step explanation:

Multiply both sides of the equation by

screen shot has my step by step

Hope it was helpful

Zanzabum3 years ago
3 0

Answer:

x=-70

Step-by-step explanation:

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An artist wants to reduce the size of a drawing using a scale factor of 3:1 . The original drawing has an area of 720 square inc
leonid [27]
Ratio is 3:1 and the original area is 720. So 3/1 is equivalent to 720/x . X is the missing number. Set up like
3/1=720/x
Cross multiply you get 3x=720
Solve for x which is 720/3
New area is 240 square inches
7 0
4 years ago
Read 2 more answers
What is the average rate of change for ƒ(x) = −2x + 70 over the interval 2 ≤ x ≤ 6?
Anvisha [2.4K]

Answer:

The average rate of change is -2

Step-by-step explanation:

we know that

To find out the average rate of change, we divide the change in the output value by the change in the input value.

In a linear function the average rate of change is a constant and is equal to the slope of the function

The linear function in slope intercept form is equal to

f(x)=mx+b

where

m is the slope or unit rate of the linear function

b is the y-intercept or initial value of the linear function

In this problem we have

f(x)=-2x+70

so

m=-2\\b=70

therefore

The average rate of change is -2

4 0
4 years ago
Pleaseeeeee help meeee answer number 3,5 and 7 they are hard for me to do
Liula [17]

Answer:

5. 52+56 < 49x -46x

108< 3x

108/3< 3x/3

36

8 0
2 years ago
Which of the following are not true about functions
Ksju [112]
What are the options?
4 0
3 years ago
I need help on #10
Ede4ka [16]
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)

Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
6 0
3 years ago
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