To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:
7) (x)=x³-6x²+8x
(x)=x(x³-6x²+8)
(x)=(x-4)(x-2)x
The lenght is: x
The height is= (x-4)
8) √(2x+8)-6=4
1. You need to clear the variable "x". Then:
√(2x+8)=4+6
√(2x+8)=10
(√2x+8)²=10²
2x+8=100
2x=100-8
x=92/2
x=46
9) l4x+3l=9+2x
1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:
2. Negative:
l4x+3l=9+2x
-4x-3=9+2x
-4x-2x=9+3
-6x=12
x=12/-6
x=-2
3. Positive:
l4x+3l=9+2x
4x+3=9+2x
4x-2x=9-3
2x=6
x=6/2
x=3
Answer:
D. Expression for Nick's distance from starting point= 6+(-4)+2
Step-by-step explanation:
Finding expression for each scenario:
A.
Number of boxes processed on on Monday =6 boxes
Number of boxes processed on on Tuesday =4 boxes
Number of boxes processed on on Wednesday =2 boxes
Expression for total boxes processed on these 3 days = 
B.
Temperature of Suma's city at noon = 6°C
Temperature of Suma's city at 8pm = 4°C
Temperature of Suma's city at noon next day = 2°F
Total temperature change = cannot be determined as all measurements are not in same units.
C
Money put on Monday = $6
Money put in Wednesday =$4
Money withdrew on Saturday = $2
Expression for balance of Re'onna's piggy bank = 
D
Distance ran north =6 miles
Distance ran south(back) = 4 miles
Distance ran north again = 2 miles
Expression for Nick's distance from starting point= 6+(-4)+2
Can u take a picture please?
The sampling error if the grade point averages for 10 randomly selected students from a class of 125 students has a mean of x =2. is A. -0.7.
Given:
Random number=10
mean of x=2
population=125
mean of p=2.7
Using this formula
Sampling error=x− μ
Where:
x= sample mean=2
μ=population mean=2.7
Let plug in the formula
Sampling error=2-2.7
Sampling error=-0.7
Inconclusion the sampling error is A.-0.7.
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Answer: When scaling something, only the lengths of the sides change, the angles would remain the same. The answer is stay the same.
Step-by-step explanation:
