Answer:
In standard form it is x^4 - 12x^3y + 54x^2y^2 - 108x y^3 + 81y^4.
Step-by-step explanation:
(3y)^4 + 4C1(3y)^3(-x) + 4C2(3y)^2(-x)^2 + 4C3(3y)(-x)^3 + (-x)^4
= 81y^4 - 108y^3x + 54y^2x^2 - 12yx^3 + x^4
This is how I would do it:
-8x=28-4y divide the entire equation by 4
-2x=7-y Put y back on the left and put x on the right
y=7-2x.
Answer:
add 18 to both sides, giving you 3x = 96
Answer:
There could be many but one of them is
(m+5)(m-9)=0....
