Answer:
c
Explanation:
Random distribution of the Isopods should be 50/50 in A and B.
Chi-square = 
where O = observed frequency and E = expected frequency
Chamber O E Chi-square
A 18 10 
= 6.4
B 2 10 
= 6.4
<em>Total Chi-square </em>= 6.4 + 6.4 = 12.8
<em>Degree of freedom</em> = 2 - 1 = 1
<em>Tabulated Chi-square</em> (α = 0.05) = 3.8415
The calculated Chi-square exceeds the critical value, hence, it is significant and not due to random.
<em>The correct option is </em><em>c</em><em>.</em>
D. He controlled variables by studying one or two traits at a time
Answer:
barbiturate/sedatives
Explanation:
Lateralization is a process of studying the split functions of the brain hemispheres. The most common test used for testing lateralization is obtained from sodium amytal studies. In this study a barbiturate or a sedative is injected into the carotid artery either left or the right artery. So, till the time the barbiturate hampers the functioning of any hemisphere, the functions associated with that hemisphere also gets hampered or are sustained for a while. This technique is of invasive nature
Answer:
open cluster
Explanation:
As the name suggests, an open cluster is a star cluster that is loose and disorganized.
